It exists 10 factors of 224, if an integer is a factor of 224 then it exists another natural number we can multiply
by that integer to get 224. Here are the 10 factors of 224: **1; 2; 4; 7; 8; 14; 16; 28; 32; 56; 112; 224.**

Example: 8 is a factor of 224 because 8 multiplied by 28 is equal to 224.

If the product of two whole numbers is equal to 224 then those two whole numbers are factors of 224. So 28 and 8 are both factors of 224.

Remark: The division of 224 by one of its factors gives as quotient another factor of 224 and zero remainder, a factor of 224 is also a divisor of 224.

Example: 14 is a factor of 224, so 224 divided by 14 gives as quotient 16 which is another factor of 224 and the remainder of the division is equal to zero (224/14=16).

Here are all the multiplications of two integers that the product is equal to 224:**1*224=224; 2*112=224; 4*56=224; 7*32=224; 8*28=224; 14*16=224.**

**Here are the prime factors of 224: 2; 7.**

**The prime factorization of 224 is: 2^5*7.**

224 is a multiple of 2 then 224 is an even number.

**find the lcm and the gcf of two integers**

**find the first n multiples of an integer**

**find the multiples of an integer inside an interval**

**retrieve prime numbers inside an interval**

**retrieve the irreducible value of a fraction**

Example: 8 is a factor of 224 because 8 multiplied by 28 is equal to 224.

If the product of two whole numbers is equal to 224 then those two whole numbers are factors of 224. So 28 and 8 are both factors of 224.

Remark: The division of 224 by one of its factors gives as quotient another factor of 224 and zero remainder, a factor of 224 is also a divisor of 224.

Example: 14 is a factor of 224, so 224 divided by 14 gives as quotient 16 which is another factor of 224 and the remainder of the division is equal to zero (224/14=16).

Here are all the multiplications of two integers that the product is equal to 224:

224 is a multiple of 2 then 224 is an even number.